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\(-\sqrt{320} \)

 

How do i go about solving this?

 Apr 13, 2016
edited by Guest  Apr 13, 2016
 #1
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Just take the square root of 320 and put - in front of it.

-sqrt(320)=-17.888.....etc. That is it.

 Apr 13, 2016
 #2
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One would think that it would be approximately -17.888, because the square root of 320 is 17.888.

 

However, it isn't.

 

Put this into the calculator:

 

\((-2)^2\)

 

What does it come up with? It should be 4. Not -4. This is because a negative multiplied by a negative is a positive. Because of this, the square root of -320 will not be -17.888, as -17.888 sqaured will be 320, and not -320.

 

So the question remains: what is the answer? It can't be -17.888, nor can it be 17.888, for those are both square roots of 320. The answer is acually 17.888*i, or 17.888i. What is i you ask? i is actually the simbol that mathematicians have used for the square root of -1. And because \( \sqrt{-1} = i\)

This means that \( -\sqrt{320}=17.888i\)

 Apr 13, 2016
edited by Guest  Apr 13, 2016
edited by Guest  Apr 13, 2016
edited by Guest  Apr 13, 2016
edited by Guest  Apr 13, 2016
 #3
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Guest #1 is correct.  The question asks for the negative of the square root of 320.  The square root of 320 is 17.88... and so the negative of this is -17.88... 

 Apr 13, 2016

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