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sqrt(6^2+3^2) in surd form?angry

 Oct 13, 2016
 #1
avatar+14985 
0

sqrt(6^2+3^2) in surd form? ​

 

\(\sqrt{6^2+3^2 }\)

 

Klick ∑LaTeX

remove   x = {-b \pm \sqrt{b^2-4ac} \over 2a}

enter  \sqrt{6^2+3^2}

give  OK  ⇒

 

\({\color{blue}\sqrt{6^2+3^2}}\)    laugh !

 

Thanks Alan!

\({\color{blue}\sqrt{6^2+3^2}=\sqrt{45}=\sqrt{5\times9}=3\times\sqrt{5}}\)

 

{\color{blue}\sqrt{6^2+3^2}=\sqrt{45}=\sqrt{5\times9}=3\times\sqrt{5}}

 

Greetings asinus :- )  laugh !

 

\(\)

 Oct 13, 2016
edited by asinus  Oct 13, 2016
edited by asinus  Oct 13, 2016
 #2
avatar+33653 
0

sqrt(6^2+3^2) → sqrt(45) → sqrt(5*9) → sqrt(5*3^2) → 3sqrt(5)

.

 Oct 13, 2016

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