sqrt(x+1)+x-11=0 Could you please show me how to do this? I'm lost.

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$${\sqrt{{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{11}} = {\mathtt{0}}$$

$${\sqrt{{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}}} = {\mathtt{11}}{\mathtt{\,-\,}}{\mathtt{x}}$$            |  quadrieren

x + 1 = 121 -22x +x²

x² -23x - 122 = 0

x(1) = 23/2 + sqrt( 11.5² +122 )             $${\frac{{\mathtt{23}}}{{\mathtt{2}}}}{\mathtt{\,\small\textbf+\,}}{\sqrt{{{\mathtt{11.5}}}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{122}}}} = {\mathtt{27.445\: \!218\: \!719\: \!101\: \!974\: \!1}}$$

x(2) = $${\frac{{\mathtt{23}}}{{\mathtt{2}}}}{\mathtt{\,-\,}}{\sqrt{{\left({\frac{{\mathtt{23}}}{{\mathtt{2}}}}\right)}^{{\mathtt{2}}}{\mathtt{\,\small\textbf+\,}}{\mathtt{122}}}} = -{\mathtt{4.445\: \!218\: \!719\: \!101\: \!974\: \!1}}$$