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sqrt(x+3)=8/sqrt(x-9)

 May 15, 2015

Best Answer 

 #1
avatar+128579 
+5

√(x+3)=8/√(x-9)     multiply both sides by  √(x-9)

 

√(x-9) * √(x + 3)  = 8

  

√[(x - 9)*(x + 3) ] = 8     square both sides

 

(x - 9) (x + 3) = 64 

 

X^2 - 6x - 27 = 64

 

x^2 - 6x - 91 = 0       factor

 

(x - 13) ( x + 7) = 0      setting each factor to 0 we have    x = 13   or  x = -7    { reject -7 }

 

So

 

x = 13

 

  

 May 15, 2015
 #1
avatar+128579 
+5
Best Answer

√(x+3)=8/√(x-9)     multiply both sides by  √(x-9)

 

√(x-9) * √(x + 3)  = 8

  

√[(x - 9)*(x + 3) ] = 8     square both sides

 

(x - 9) (x + 3) = 64 

 

X^2 - 6x - 27 = 64

 

x^2 - 6x - 91 = 0       factor

 

(x - 13) ( x + 7) = 0      setting each factor to 0 we have    x = 13   or  x = -7    { reject -7 }

 

So

 

x = 13

 

  

CPhill May 15, 2015

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