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sqrt3(2+sqrt(5) + sqrt3(2-sqrt(5) is equal to 1. Why?

 Sep 25, 2014

Best Answer 

 #3
avatar+118658 
+8

sqrt3(2+sqrt(5) + sqrt3(2-sqrt(5)

 

$${\sqrt[{{\mathtt{3}}}]{{\mathtt{2}}{\mathtt{\,\small\textbf+\,}}{\sqrt{{\mathtt{5}}}}{\mathtt{\,\small\textbf+\,}}{\sqrt[{{\mathtt{3}}}]{{\mathtt{2}}{\mathtt{\,-\,}}{\sqrt{{\mathtt{5}}}}}}}} = {\mathtt{1.535\: \!173\: \!791\: \!362\: \!287\: \!2}}$$

 

You need to fix the brackets.     

 Sep 26, 2014
 #1
avatar+118658 
+8

There is not a balanced number of brackets so I do not know what the question is.  

 Sep 25, 2014
 #2
avatar
+3

Plug it into the calculator to see what I mean

 Sep 26, 2014
 #3
avatar+118658 
+8
Best Answer

sqrt3(2+sqrt(5) + sqrt3(2-sqrt(5)

 

$${\sqrt[{{\mathtt{3}}}]{{\mathtt{2}}{\mathtt{\,\small\textbf+\,}}{\sqrt{{\mathtt{5}}}}{\mathtt{\,\small\textbf+\,}}{\sqrt[{{\mathtt{3}}}]{{\mathtt{2}}{\mathtt{\,-\,}}{\sqrt{{\mathtt{5}}}}}}}} = {\mathtt{1.535\: \!173\: \!791\: \!362\: \!287\: \!2}}$$

 

You need to fix the brackets.     

Melody Sep 26, 2014

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