Square ABCD has vertices A(-2,-3), B(4,-1), C(2,5) and D(-4,3). what is the length of a side of the square?

Hi Jaylifee,

Welcome to Web2.0calc forum!

Assuming that it really is a square, you just need to find the distance between any 2 consecutive vertices.

That is , AB or BC or CD or CA

I am going to use BC because it looks easiest.

$$d=\sqrt{(2-4)^2+(5--1)^2}\\\\
d=\sqrt{(-2)^2+(6)^2}\\\\
d=\sqrt{4+36}\\\\
d=\sqrt{40}\\\\
d=\sqrt{4}\times\sqrt{10}\\\\
d=2\sqrt{10}\\\\$$

 

I also drew a picture just to check it really was a square.

The forum attachment upload is not working but I put the picture here.

http://gyazo.com/5d3dad50d0a441f5630de752714c0928