+0  
 
0
354
6
avatar+621 

How many different integers are there such that the square of the square of the integer is a two-digit integer?

mathtoo  Dec 29, 2017
 #1
avatar+93911 
+2

Write down a list of squared numbers and count them

1^2=1                  1^2=1

2^2=2*2=4          4^2=16

3^2=3*3=9           9^2=81

etc

 

For every positive number there will be a negative one as well, so you better double your answer :)

Melody  Dec 29, 2017
edited by Melody  Dec 29, 2017
edited by Melody  Dec 29, 2017
 #6
avatar+93911 
+2

The square of the square is a power of 4

 

1^4 id 1 digit

2^4=16 which is 2 digit

3^4=81 so that works

4^4=256 which is too big

so I get

 

2, 3, -2, and -3  that is it.

 

4 integers meet this requirment :)

Melody  Dec 29, 2017
 #2
avatar+3277 
0

what's the answer?

tertre  Dec 29, 2017
 #3
avatar+7336 
+1

*edit*

 

This answer was wrong...I agree with Melody.

hectictar  Dec 29, 2017
edited by hectictar  Dec 29, 2017
 #4
avatar+3277 
0

hmm, not getting the same answer..

tertre  Dec 29, 2017
 #5
avatar+7336 
0

What answer are you getting?   smiley

hectictar  Dec 29, 2017

27 Online Users

avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.