How many different integers are there such that the square of the square of the integer is a two-digit integer?

Write down a list of squared numbers and count them

1^2=1 1^2=1

2^2=2*2=4 4^2=16

3^2=3*3=9 9^2=81

etc

For every positive number there will be a negative one as well, so you better double your answer :)

The square of the square is a power of 4

1^4 id 1 digit

2^4=16 which is 2 digit

3^4=81 so that works

4^4=256 which is too big

so I get

2, 3, -2, and -3 that is it.

4 integers meet this requirment :)

what's the answer?

*edit*

This answer was wrong...I agree with Melody.

hmm, not getting the same answer..

What answer are you getting?