How many different integers are there such that the square of the square of the integer is a two-digit integer?
Write down a list of squared numbers and count them
1^2=1 1^2=1
2^2=2*2=4 4^2=16
3^2=3*3=9 9^2=81
etc
For every positive number there will be a negative one as well, so you better double your answer :)
The square of the square is a power of 4
1^4 id 1 digit
2^4=16 which is 2 digit
3^4=81 so that works
4^4=256 which is too big
so I get
2, 3, -2, and -3 that is it.
4 integers meet this requirment :)
what's the answer?
*edit*
This answer was wrong...I agree with Melody.
hmm, not getting the same answer..
What answer are you getting?
+817 
