What are the dimensions of the largest square peg which can be inserted in a hole 8 inches in diameter? Thanks.
+37099 The diagonal of the square will be the diameter of the circle 8"
the triangle formed will be a right triangle with equal length sides
a^2 + b^2 = 8^2
2a^2 = 8^2
a^2 = 32
a = side length = sqrt32=5.65 inches
+37099 The diagonal of the square will be the diameter of the circle 8"
the triangle formed will be a right triangle with equal length sides
a^2 + b^2 = 8^2
2a^2 = 8^2
a^2 = 32
a = side length = sqrt32=5.65 inches
0 the last time I did that much math Electric pavlov, was when i was forced to calculate the amount of big black male organs i could fit in my butt at one time
