We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website.
Please click on "Accept cookies" if you agree to the setting of cookies. Cookies that do not require consent remain unaffected by this, see
cookie policy and privacy policy.
DECLINE COOKIES

A square prism and square pyramid have the same base and the smae surface area. Show that the slant height, l, of the pyramid is l= (5/2)s where s is the length of the base.

Shonk May 6, 2018

edited by
Guest
May 7, 2018

#1**0 **

I'm pretty sure it is unanswerable with that limited info, but I am rusty on this topic.

melvsky May 6, 2018

#2**0 **

There's nothing wrong with the question, there is sufficient information, look at it again.

Guest May 6, 2018

#3**+1 **

SA of square pyramid =[Base Area] + 1/2 × Perimeter × [Slant Length ] SA of square prism = 2 × Base Area + Base Perimeter × Length

Let the base area of both = S^2

The perimeter of both =4S

S^2 + [1/2*4S] * L = [2 * S^2] + 4S*S , solve for L=Slant Height

2 L S + S^2 = 6 S^2

Subtract S^2 from both sides:

2 L S = 5 S^2

Divide both sides by 2 S:

**L = 5/2S - Slant Length[Height] of the pyramid.**

Guest May 6, 2018

#4**+1 **

In your equation you assumed that the length of the square prism is equal to s (the side of the base), isn't correct as if these lines were equal then the shape would be a cube rather than a square prism, nonetheless using my differing aprroach doesn't give an answer, so I assume the question wasn't written properly, as you need to assume the square prism is a cube to solve for l.

Shonk
May 6, 2018