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In the square pyramid shown below, the diagonal length FC = 16√2 centimeters and the height of the pyramid is 7 centimeters. Find the slant height AD of the pyramid, to the nearest tenth. Show your work with reasoning for each step.

 

 Mar 31, 2021
 #1
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so since we know FC is 16sqrt2, the we know the side length is 16, 16^2 + 16^2 = (x)^2, x = 16sqrt2

 

then we use half the length of the square since we can make a triangle using the midpoint of the square.

7^2 + 8^2 = c^2, c = sqrt113 or roughly 10.63

 Mar 31, 2021
 #2
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Since   the  base  is a square.....a side of the  base =  FC / sqrt (2)  =   16

 

The slant  height =   sqrt [  (16 / 2)^2  + 7^2 ]   =  sqrt [ 8^2 + 7^2 ] =  sqrt  [ 64 + 49 ]   =

 

sqrt [ 113  ]  ≈   10.6 cm

 

 

cool cool cool

 Mar 31, 2021

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