3x + x√3 = 3 + 3√3
$$x(3+\sqrt3)=3(1+\sqrt3)\\\\
x=\frac{3(1+\sqrt3)}{(3+\sqrt3)}\\\\
x=\frac{3(1+\sqrt3)}{(3+\sqrt3)}\times \frac{(3-\sqrt3)}{(3-\sqrt3)}\\\\
x=\frac{3(3+2\sqrt3-3)}{(9-3)}\\\\
x=\frac{3(2\sqrt3)}{6}\\\\
x=\sqrt3\\\\$$
How about that!
