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How do you find the square root of negative 28?

 Oct 20, 2015

Best Answer 

 #1
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+5

How do you find the square root of negative 28

 

Simplify the following:
sqrt(-28)

sqrt(-28) = sqrt(-1) sqrt(28) = i sqrt(28):
i sqrt(28)

sqrt(28)  =  sqrt(4×7)  =  sqrt(2^2×7):
i sqrt(2^2 7)

sqrt(2^2 7)  =  sqrt(2^2) sqrt(7)  =  2^(2/2) sqrt(7)  =  2 sqrt(7):
Answer: | 
| i×2 sqrt(7)

=2i sqrt(7)

 Oct 21, 2015
 #1
avatar
+5
Best Answer

How do you find the square root of negative 28

 

Simplify the following:
sqrt(-28)

sqrt(-28) = sqrt(-1) sqrt(28) = i sqrt(28):
i sqrt(28)

sqrt(28)  =  sqrt(4×7)  =  sqrt(2^2×7):
i sqrt(2^2 7)

sqrt(2^2 7)  =  sqrt(2^2) sqrt(7)  =  2^(2/2) sqrt(7)  =  2 sqrt(7):
Answer: | 
| i×2 sqrt(7)

=2i sqrt(7)

Guest Oct 21, 2015
 #2
avatar+129840 
+5

Remember that   sqrt( -1)   = i   ....so we have

 

sqrt(-28)  =

 

sqrt (-1 * 4 * 7)  =

 

sqrt (-1) * sqrt(4) * sqrt(7)  =

 

i * 2 * sqrt(7)   or    just     

 

2*sqrt(7) i

 

 

cool cool cool

 Oct 21, 2015

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