(square root of 3) tan^2 x= tan x, Solve for -180

$$\\\sqrt3tan^2x=tanx\\ \sqrt3tan^2x-tanx=0\\ tanx(\sqrt3tanx-1)=0\\ tanx=0 \quad or \quad \sqrt3tanx-1=0\\ tanx=0 \quad or \quad tanx=\frac{1}{\sqrt3}\\ -180^0,\;\;0^0,\;\;180^0,\quad or \quad -150^0,\;\;30^0\\ $so all the solutions are$\\ x=-180^0,\;\;-150^0,\;\;0^0,\;\;30^0,\;\;180^0$$

i see you seven people online. I see you and I'm judging you for not answering this question. But seriously please help me.

Thank you very much for your solution. Feel silly for not realising all it takes is some simple equation re-arranging.

May be a silly question but can -30 be a solution? Why/why not?

NEVERMIND i got it now. I was thinking of the wrong thing