4√ x20y28

For the first one, we have

4√( x20y28) = 4√ (x(5*4)y(4*7)) = 4√ (16*5*7*xy) = 16√(35xy ).... (Note....We took out a "4" and multiplied it by the one on the "outside")

I don't understand your second question.....are we wanting to solve this for "x"....  ???

Sorry that it posted weird! I will try to retype that question...:

x√4=16/18

Does that make sense CPhill?

Well....the square root of 4 = 2....so we have....

2x = 16/18

Can you take it from here????

Do i simplify 16 and18?

OK.....do that first.....

8/9?

-Natasza:)

OK...so far, so good.....so we have

2x = 8/9      .....now.......how do we get x by itself???

Is that how i do a squareroot??

OK...so we have

2x = 8/9

And we're trying to solve for x.....we've finished the "square root" part

What if I multiplied both sides by 1/2.....what would happen???

Okay! Got it! THank you!