squaring a binomial

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squaring a binomial

(4x-3)2

Guest Mar 31, 2015

+118616

+5

Best Answer

This is the short cut

$$(4x-3)^2\\\\
=(4x)^2+2(4x*-3)+(-3)^2\\\\
=16x^2-24x+9\\\\\\
$that is$\\\\
(a+b)^2=a^2+2ab+b^2\\
and\\
(a-b)^2=a^2-2ab+b^2\\$$

Melody Mar 31, 2015

Melody · Answer 1 · 2015-03-31T10:10:07

This is the short cut

$$(4x-3)^2\\\\
=(4x)^2+2(4x*-3)+(-3)^2\\\\
=16x^2-24x+9\\\\\\
$that is$\\\\
(a+b)^2=a^2+2ab+b^2\\
and\\
(a-b)^2=a^2-2ab+b^2\\$$