"The mean time taken by admin staff in a certain company to log on to their computer network is 70 seoncs with a standard deviation of 6 seconds. Assuming these times are normally distirbuted, what percentage of admin staff would have logged on with a minute" I have no idea how to attempt this question, any tips? thank you for any help.
standard deviation = sqrt(n p *(1-p))
where n = amount of people and p = percentage of deviation
Approximately 4.8% according to Wolfram Alpha: