+0  
 
0
224
1
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standard deviation

data
.22
.32
.11
.33
.12
Guest Apr 30, 2012
 #1
avatar+3076 
0
[input]data=(0.22,0.32,0.11,0.33,0.12); xs=sum(data[x],x=1..5)/5; sqrt( 1/(5-1)* sum( (data[x]-xs)^2 ,x=1..5) )[/input]
admin  May 1, 2012

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