How do I convert y=-3/5(x-0)^2+3 into standard form
y=-3/5(x-0)^2+3 =
y = -3/5 x^2 + 3 Is this the standard form? ( I don't know)
y + 3/5 x^2 -3 = 0 Is the the Standard form you are looking for?
5y + 3x^2 - 15 = 0 Another form.......they are all equal .....