Daniel has 40 coins that are either Nickels or Dimes. The total Value of the coins is $2.85. How many of each coin does Daniel have?
The answer is 17 dimes & 23 nickels. Show work
+178 Let the number of nickels be x, and the number of dimes be y. Then, we can set up two equations.
\(x+y=40, 0.05x+0.10y=2.85. \)
We can then multiply both sides of the second equation by 20 to get \(x+2y=57\) so \(y=17, x=23.\)
So, the answer is that there are 17 dimes, 23 nickels
+36915 40 coins
nickles = n value = 5 n
dimes = (40-n) value = 10 (40 -n) summed = 285
5n + 10 (40-n) = 285 solve for n then d = 40 -n
