Find the area under the standard normal curve over the interval specified below. Between z = –2 and z = 1.2
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+128475 Thanks, Melody, for that resource....!!!
By hand we can do this:
Area between z = 0 and z = 1/2 = .6915 - .5000 = .1915
Area between z = 0 and z = -2 = .5000 - .0228 = .4772
The probability (area) is the sum of these
So.....the probability (area) is .1915 + .4772 = .6687
