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# Statistics

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Last years freahman class at big state university totaled 5,305 students. Of those l, 1,258 received a merit scholarship to help offset tuition cost their freshman year (although the amount varied per student). The amount a student received was N($3,456,$478). If the coat of full tuition was $4,250 last year, what percentage of students who received a merit scholarship did not receive enough to cover full tutoring? Aug 7, 2022 ### 5+0 Answers #1 +2667 0 Wait... so each student received 3,456,478 dollars? Are you sure your question is typed correctly? Aug 7, 2022 #2 +33619 +1 I think N($3,456, $478) is meant to indicate a normal distribution with mean$3,456 and standard deviation $478 (or possibly a variance of$478, as both forms are common, and the poster hasn't specified which).

Alan  Aug 8, 2022
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Hi Alan, nice seeing you here!

The question is written in an ambiguous fashion, and it is unclear what was meant.

BuilderBoi  Aug 8, 2022
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I suspect the following is what is required:

Alan  Aug 8, 2022
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BuilderBoi, if you just used a kitchen scale, it would have resolved the ambiguity by  indicating that N($3,456,$478) is in the form of $$\mathbb{N}(\mu, \sigma)$$ in this case there is no need for pot-laced candy or mushroom tea (though it might help ).

Recently, I saw a demonstration of very sophisticated kitchen scale at university. This scale connects to an AI-nerualnetwork. The scale’s sensors along with the AI identify the foods, caloric values, glycemic index, and other parameters. The AI also calculates the mean probable weight gain (with a standard deviation), based on the metabolic parameters of the consumer. It’s easy to program the parameters: the consumer need only to stand and then sit on the scale for 8 seconds, and then spit on a sensor. The demonstrated scale had a mass/weight limit of 450Kg –well above the weight of the largest tub-of-lard in attendance.

During the demonstration, one of the spectators plopped a bag of pot-laced candy on the scale. The AI correctly identified the contents and caloric value, but indicated an 85% probability of weight gain at a mean of (28.7) times the maximum value for the calorie count.

The engineer-tech, who was demonstrating the scale, queried the AI for an explanation. The AI extrapolated the stats for $$\Delta9THC$$ causing the munchies in a standard population; from this, a probability of weight gain is calculated beyond the caloric value of the weighed food.

It is amazing how innovative technology can create a kitchen scale that can construct and solve statistical problems.  You should get one as soon as they are on the market.

GA

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GingerAle  Aug 10, 2022
edited by Guest  Aug 10, 2022