Assume that a procedure yields a binomial distribution with a trial repeated n times. Use the binomial probability formula to find the probability of x successes given the probability p of success on a single trial. nequals7, xequals5, pequals0.75
\(P[x] = \dbinom{7}{x} p^x (1-p)^{7-x} = \\ \dbinom{7}{5} (0.75)^5 (0.25)^2\\ \text{and I leave you to crunch those numbers}\)
