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x-2y=-2

x^2-y^2=7

 Feb 2, 2015

Best Answer 

 #1
avatar+26367 
+5

x-2y=-2       x^2-y^2=7

$$x-2y=-2 \qquad x=2y-2 \\\\
x^2-y^2=7 \qquad (2y-2)^2-y^2=7\\
4y^2-8y+4-y^2=7\\
3y^2-8y+4=7\\
3y^2-8y-3=0\\\\
\small{\text{
$
y_{1,2}=\dfrac{8\pm\sqrt{64-4*3*(-3)} } {2*3}
=\dfrac{8\pm\sqrt{64-36} } {6}
=\dfrac{8\pm\sqrt{100} } {6}
=\dfrac{8\pm10 } {6}
$
}}\\\\
\small{\text{
$
y_1=\dfrac{8+10 } {6}=\dfrac{18 } {6}=3
$
}}\\\\
\small{\text{
$
y_2=\dfrac{8-10}{6}=-\dfrac{2}{6}=-\dfrac{1}{3}
$
}}\\\\
\small{\text{
$
x_1=2*3-2 = 4
$
}}\\
\small{\text{
$
x_2=2*(-\frac{1}{3})-2 = -2\frac{2}{3}
$
}}$$

 Feb 3, 2015
 #1
avatar+26367 
+5
Best Answer

x-2y=-2       x^2-y^2=7

$$x-2y=-2 \qquad x=2y-2 \\\\
x^2-y^2=7 \qquad (2y-2)^2-y^2=7\\
4y^2-8y+4-y^2=7\\
3y^2-8y+4=7\\
3y^2-8y-3=0\\\\
\small{\text{
$
y_{1,2}=\dfrac{8\pm\sqrt{64-4*3*(-3)} } {2*3}
=\dfrac{8\pm\sqrt{64-36} } {6}
=\dfrac{8\pm\sqrt{100} } {6}
=\dfrac{8\pm10 } {6}
$
}}\\\\
\small{\text{
$
y_1=\dfrac{8+10 } {6}=\dfrac{18 } {6}=3
$
}}\\\\
\small{\text{
$
y_2=\dfrac{8-10}{6}=-\dfrac{2}{6}=-\dfrac{1}{3}
$
}}\\\\
\small{\text{
$
x_1=2*3-2 = 4
$
}}\\
\small{\text{
$
x_2=2*(-\frac{1}{3})-2 = -2\frac{2}{3}
$
}}$$

heureka Feb 3, 2015

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