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3a^+4a=2a^2-2a-9 

 

Must write in Standard Form and Solve.

Guest May 22, 2017
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I think this is the equation:

3a^2 + 4a = 2a^2 - 2a - 9

 

Subtract 2a^2 from both sides of the equation.

a^2 + 4a = - 2a - 9

 

Add 2a to both sides of the equation.

a^2 + 6a = -9

 

Add 9 to both sides of the equation.

a^2 + 6a + 9 = 0           \(\leftarrow\)          I think this is the standard form of the equaion.

 

Now we can factor the left side like this

(a + 3)(a + 3) = 0

(a + 3)^2 = 0

 

Take the square root of both sides.

a + 3 = 0

 

Subtract 3 from both sides of the equation.

a = -3

hectictar  May 22, 2017

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