The sum of the interior angles of the quadrilateral in the center = 360°
Call these angles A, B , C and D
And each of these angles is supplemental to an exterior angle of a triangle
Call these angles (180 - A) , (180 - B) , (180 - C) and (180 - D)
And by the exterior angle theorem, each of these exterior angles is equal to the sum of the two remote interior orange angles in their respective triangles
So....the sum of all the orange angles = (180 - A) + (180 - B) + (180 - C) + (180 - D) =
4(180) - (A + B + C + D) =
720 - 360 =
360°