\(\frac{2x+1}{3}+7=\frac{3x-1}{4}\) Multiply both sides of the equation by 4 .
\(4\,*\,(\frac{2x+1}{3}+7)=3x-1 \\~\\ \frac{4(2x+1)}{3}+28=3x-1\) Distribute the 4 .
\(\frac{8x+4}3+28=3x-1 \\~\\ 3\,*\,(\frac{8x+4}3+28)=3\,*\,(3x-1) \\~\\ 8x+4+84=9x-3\) Multiply both sides of the equation by 3 and distribute.
\(8x+88=9x-3\) Subtract 8x from both sides of the equation.
\(88=x-3\) Add 3 to both sides of the equation.
\(91=x\)
Notice that we could have multiplied both sides by 12 to begin with and this would get rid of both fractions in one step.