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If the system of equations 2x - y = a, 3y - 6x = b has a solution, find a / b, assuming b is not equal to 0.

 Oct 2, 2019
 #1
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\(2x - y = a\\ -6x+3y=b\\ \text{Add 3 times equation 1 to equation 2}\\ 0=3a+b\\ b = -3a\\ \dfrac a b = \dfrac{a}{-3a} = -\dfrac 1 3\)

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 Oct 2, 2019
 #2
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Thanks for the help!

Guest Oct 2, 2019

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