3x-4y=-15 and 5x+y=-2
We can write the second equation as y = -2-5x ......and substituting this into the first equation for y, we have
3x -4(-2-5x) = -15 simplify
3x + 8 + 20x = -15
23x + 8 = -15 subtract 8 from both sides
23x = - 23 divide both sides by 23
x = -1 and y = -2 -5(-1) = -2 + 5 = 3
So (x, y) = (-1, 3)
3x-4y=-15 and 5x+y=-2
We can write the second equation as y = -2-5x ......and substituting this into the first equation for y, we have
3x -4(-2-5x) = -15 simplify
3x + 8 + 20x = -15
23x + 8 = -15 subtract 8 from both sides
23x = - 23 divide both sides by 23
x = -1 and y = -2 -5(-1) = -2 + 5 = 3
So (x, y) = (-1, 3)