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Removed question

 Oct 19, 2018
edited by jjennylove  Oct 21, 2018
 #1
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(x^2 + 8x) / (3x^2 + 3x)  -  (x^2 + 2x - 6) / (3x^2 + 3x)
[(x^2 + 8x) - (x^2 + 2x - 6)] / (3x^2 + 3x)
[x^2 + 8x - x^2 - 2x + 6] / (3x^2 + 3x)
[6x + 6] / (3x^2 + 3x) 
6(x + 1) / 3x(x + 1)
6 / 3x =2 / x

 Oct 19, 2018
 #2
avatar+708 
+1

Thank You!

jjennylove  Oct 19, 2018

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