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The sum of the first n positive even integers is \(2550\). compute the value of n.

 May 6, 2022
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Sum of first  n positive even integers  =   n  (n + 1) 

 

So

 

n ( n + 1)   =  2550

 

n^2 + n - 2550  =  0      factor as

 

(n + 51) ( n - 50)  = 0

 

The second factor set  = 0   is what we need

 

n  - 50   = 0

 

n  = 50

 

 

cool cool cool

 May 6, 2022
edited by CPhill  May 6, 2022

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