The sum of the first n positive even integers is \(2550\). compute the value of n.
Sum of first n positive even integers = n (n + 1)
So
n ( n + 1) = 2550
n^2 + n - 2550 = 0 factor as
(n + 51) ( n - 50) = 0
The second factor set = 0 is what we need
n - 50 = 0
n = 50
