What is the sum of all the five-digit positive integers in which each of the digits 1, 2, 3, 5 and 8 appear exactly once?
[11111 + 22222 + 33333 + 55555 + 88888] ==211,109
211,109 x 24 ==5,066,616 -sum of all 120 permutations of 1, 2, 3, 5, 8.
