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What is the sum of all the five-digit positive integers in which each of the digits 1, 2, 3, 5 and 8 appear exactly once?

 Jul 12, 2022
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[11111  +  22222  +  33333  +  55555  +  88888] ==211,109

 

211,109  x  24 ==5,066,616 -sum of all 120 permutations of 1, 2, 3, 5, 8.

 Jul 12, 2022

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