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Let \(x\) and \(y\) be positive real numbers such that \(\frac{1}{x + 2} + \frac{1}{y + 2} = \frac{1}{3}.\)
Find the minimum value of \(x+2y\).

 

This is under a Cauchy-Schwarz topic, so I'm assuming you have to use the inequality....please help :\]]

 Apr 27, 2020
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The minimum value is 2/3.

 May 23, 2020

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