I've literally tried to approach this problem so many ways but still can't seem to solve it.
The graph of an equation \(\sqrt{(x-3)^2 + (y+4)^2} + \sqrt{(x+5)^2 + (y-8)^2} = 20\) is an ellipse. What is the distance between its foci?
+36916 I am not sure of this answer:
An ellipse is a graph of points where the sum of the distances from two foci is a constant....
this looks like the equation for two distances from two foci
first foci would be 3 , -4 other is -5, 8
distance between these points is (3- -5)^2 + (-4 - 8)^2 = d^2
64 + 144 = d^2 d = sqrt 208
