I've literally tried to approach this problem so many ways but still can't seem to solve it.

The graph of an equation \(\sqrt{(x-3)^2 + (y+4)^2} + \sqrt{(x+5)^2 + (y-8)^2} = 20\) is an ellipse. What is the distance between its foci?

Guest Mar 18, 2020

#1**+2 **

I am not sure of this answer:

An ellipse is a graph of points where the sum of the distances from two foci is a constant....

this looks like the equation for two distances from two foci

first foci would be 3 , -4 other is -5, 8

distance between these points is (3- -5)^2 + (-4 - 8)^2 = d^2

64 + 144 = d^2 d = sqrt 208

ElectricPavlov Mar 18, 2020