Suppose a bowl contains 5 white and 5 black b***s. If 4 b***s are randomly drawn, what is the probability that the two of the b***s are whit

The total number of possible sets is given by C(10, 4)  = 210

And the ones we are interested in contain 2 white ones chosen from any 5 white ones and 2 black ones drawn from any 5 black ones

So we have

[ C(5, 2) * C(5, 2) ] / C(10, 4) =  [ 10 * 10 ] / 210  = 100 / 210  = about 47.6%

1/2 because the fractions added together equal 5/10 which simplifies to 1/2