+0  
 
-2
1153
3
avatar+2448 

I don't understand how to put it in vertex form. 

 Feb 20, 2018

Best Answer 

 #1
avatar+37146 
0

Vertex form is     a (x-h)^2 +k = 0    where h,k is the vertex   so let's start with that h,k = 6,-1

 

a (x-6)^2 +  -1 = y     (this info was given in the question)

       and the point  7,-3 given as a solution to this equation ..now we can substitute this into the equation to find 'a'

a(7-6)^2 -1 = -3

a-1 = -3

a=-2  

so the equation becomes

 

-2(x-6)^2 -1 = y

 Feb 20, 2018
edited by ElectricPavlov  Feb 20, 2018
 #1
avatar+37146 
0
Best Answer

Vertex form is     a (x-h)^2 +k = 0    where h,k is the vertex   so let's start with that h,k = 6,-1

 

a (x-6)^2 +  -1 = y     (this info was given in the question)

       and the point  7,-3 given as a solution to this equation ..now we can substitute this into the equation to find 'a'

a(7-6)^2 -1 = -3

a-1 = -3

a=-2  

so the equation becomes

 

-2(x-6)^2 -1 = y

ElectricPavlov Feb 20, 2018
edited by ElectricPavlov  Feb 20, 2018
 #2
avatar+885 
+3

Which is D. Great job!

ant101  Feb 20, 2018
 #3
avatar+2448 
+1

ty!!

RainbowPanda  Feb 20, 2018

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