Vertex form is a (x-h)^2 +k = 0 where h,k is the vertex so let's start with that h,k = 6,-1
a (x-6)^2 + -1 = y (this info was given in the question)
and the point 7,-3 given as a solution to this equation ..now we can substitute this into the equation to find 'a'
a(7-6)^2 -1 = -3
a-1 = -3
a=-2
so the equation becomes
-2(x-6)^2 -1 = y
Vertex form is a (x-h)^2 +k = 0 where h,k is the vertex so let's start with that h,k = 6,-1
a (x-6)^2 + -1 = y (this info was given in the question)
and the point 7,-3 given as a solution to this equation ..now we can substitute this into the equation to find 'a'
a(7-6)^2 -1 = -3
a-1 = -3
a=-2
so the equation becomes
-2(x-6)^2 -1 = y