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Suppose h(x)= 1/sqrtx for x>0. Does h have an inverse? If so, find h^{-1}(4). If not, enter "undef".

 Oct 25, 2017
 #1
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h (x)  = 1 / √x

 

y = 1 / √x     square both sides

 

y^2  = 1/x  

 

x = 1/y^2   swap x and y   and for y wriite  h-1(x)

 

y =  h-1(x)  = 1 / x^2

 

And     h-1(4)  =  1 / 4^2  =  1 / 16

 

 

cool cool cool

 Oct 25, 2017

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