Suppose h(x)=3-((x+4)/(x-7))

Here's the last one:

Evaluate h(9^-1)

9^-1 =  1/9

So h(1/9)  =  3 - ( 1/9 + 4) / (1/9 - 7)  =   3  - (37/9) / (-62/9)   =  3 + (37/62)  =   223/62

Hallo

Here's the first one :

Let us find the inverse for h(x)

h(x) = y = [ 3(x - 7) - (x + 4)] / (x - 7)  =   (2x - 25) / (x - 7)

y = (2x - 25) / (x - 7)

y(x - 7) = 2x - 25

yx - 7y  = 2x - 25

yx - 2x  = 7y - 25

x(y - 2)  = 7y - 25

x = ( 7y - 25 ) / (y - 2)   switch x and y

y = (7x - 25) / ( (x - 2)  = h^-1(x)

So  h^-1(9)  = (7(9) - 25) / ( 9 - 2)  = (63 - 25)/ (9 - 2)  = 38/7

Here's the second one:

Evaluate [h(9)]^-1

h(9)  = 3 - (9 + 4)/(9 - 7)  =   3 - 5/2   =  1/2

So .... [h(9)]^-1  =   (1/2)^-1  = 2