Suppose that a^2 varies inversely with b^3 If a=7 when b=3, find the value of a^2 when b=6
When b = 6, a^2 = 42.
(a^2)(b^3) = k
(49)(27) = k
(a^2)(6^3) = 49 * 27
a^2(8) = 49
a^2 = 49/8.
+30 
