Suppose that a bag contains 3 red, 9 white, and 5 blue b***s. If three b***s are taken out of the bag at once, what is the probability (rounded to 4 decimal places) that exactly two of them are blue?
+130511 The number of total sets possible is C(17,3) = 680
But, we're only interested in those that contain 2 blue b***s selected from 5 and one ball selected from the other 12 = C(5,2)C(12,1) = 120 sets
So the probability is 120 / 680 = 12/68 = 3 / 17 = about .1765 or 17.65%
