Suppose that I have 6 different books, 2 of which are math books. In how many ways can I stack my 6 books on a shelf if I want a math book on both ends of the stack?
To elaborate on Melody's answer....we can have either math book at both ends...so that's two ways to arrange those.
And, in the "middle,' the other 4 books can be arranged in 4! = 24 ways.
So .. 2 x 4! = 2 x 24 = 48 ways
2*4! =
$${\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{4}}{!} = {\mathtt{48}}$$
Thanks Chris,
You are right I do not explain these types of answers very well. Thanks for the extra explanation. :)