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Suppose that tan(t)=7/5 and that t is in the 3rd quadrant. Find the exact value of sec(t).

Deathstroke_rule  Apr 7, 2017
 #1
avatar+89775 
+2

x and y are negative in the 3rd quadrant.....so....

 

tan (t)   = y / x   = -7/-5   = 7/5   ...and.....

 

sec(t)   = r / x    where r  =   sqrt (x^2 + y^2)  =  sqrt (5^2 + 7^2)  =

sqrt (49 + 25) = sqrt (74)

                                            

 

So......

 

sec(t)   =  sqrt (74) / -5  =  -sqrt(74) /5

 

 

 

cool cool cool 

CPhill  Apr 7, 2017

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