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Suppose the polynomial p(x)=x^3+ax^2+bc+c has the property that the mean of its zeroes, the product of its zeroes, and the sum of its coefficients are all equal. If the y-intercept of the graph of y=p(x) is 2, what is b?

 Aug 1, 2016

Best Answer 

 #2
avatar+118608 
+16

Suppose the polynomial p(x)=x^3+ax^2+bc+c has the property that the mean of its zeroes, the product of its zeroes, and the sum of its coefficients are all equal. If the y-intercept of the graph of y=p(x) is 2, what is b?

 

for this answer I will assume it is a typo

 

The y intercept is the constant so c=2

 

\(p(x)=x^3+ax^2+bx+c\\ p(x)=x^3+ax^2+bx+2\\\)

\(\mbox{Let the zeros be }\;\alpha,\;\; \beta, \;\;and \;\; \gamma\\ \alpha+\beta+\gamma=\frac{-a}{1}\quad so \\ \frac {\alpha+\beta+\gamma}{3}=\frac{-a}{3}\\ \alpha\beta\gamma=\frac{-c}{1}=-2\\ \mbox{The coefficients are 1, a and b}\\ so\\ \frac {\alpha+\beta+\gamma}{3}=\alpha\beta\gamma=1+a+b\\ \frac{-a}{3}=-2=1+a+b\\ a=6\\~\\ -2=1+6+b\\ -2=7+b\\ b=-9\\ \)

 Aug 1, 2016
 #1
avatar+118608 
+10

Dabae, 

Is it meant to be bc as you have entered OR is it meant to be bx   ??

 Aug 1, 2016
 #2
avatar+118608 
+16
Best Answer

Suppose the polynomial p(x)=x^3+ax^2+bc+c has the property that the mean of its zeroes, the product of its zeroes, and the sum of its coefficients are all equal. If the y-intercept of the graph of y=p(x) is 2, what is b?

 

for this answer I will assume it is a typo

 

The y intercept is the constant so c=2

 

\(p(x)=x^3+ax^2+bx+c\\ p(x)=x^3+ax^2+bx+2\\\)

\(\mbox{Let the zeros be }\;\alpha,\;\; \beta, \;\;and \;\; \gamma\\ \alpha+\beta+\gamma=\frac{-a}{1}\quad so \\ \frac {\alpha+\beta+\gamma}{3}=\frac{-a}{3}\\ \alpha\beta\gamma=\frac{-c}{1}=-2\\ \mbox{The coefficients are 1, a and b}\\ so\\ \frac {\alpha+\beta+\gamma}{3}=\alpha\beta\gamma=1+a+b\\ \frac{-a}{3}=-2=1+a+b\\ a=6\\~\\ -2=1+6+b\\ -2=7+b\\ b=-9\\ \)

Melody Aug 1, 2016
 #3
avatar
+1

' The coefficients are 1, a and b ... '

Why isn't c a coefficient ?

 Aug 1, 2016
 #4
avatar
+1

The correct answer however is -11

 Feb 28, 2017

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