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Suppose the polynomial p(x)=x^3+ax^2+bc+c has the property that the mean of its zeroes, the product of its zeroes, and the sum of its coefficients are all equal. If the y-intercept of the graph of y=p(x) is 2, what is b?

 Aug 1, 2016

Best Answer 

 #2
avatar+118694 
+16

Suppose the polynomial p(x)=x^3+ax^2+bc+c has the property that the mean of its zeroes, the product of its zeroes, and the sum of its coefficients are all equal. If the y-intercept of the graph of y=p(x) is 2, what is b?

 

for this answer I will assume it is a typo

 

The y intercept is the constant so c=2

 

p(x)=x3+ax2+bx+cp(x)=x3+ax2+bx+2

Let the zeros be α,β,andγα+β+γ=a1soα+β+γ3=a3αβγ=c1=2The coefficients are 1, a and bsoα+β+γ3=αβγ=1+a+ba3=2=1+a+ba=6 2=1+6+b2=7+bb=9

 Aug 1, 2016
 #1
avatar+118694 
+10

Dabae, 

Is it meant to be bc as you have entered OR is it meant to be bx   ??

 Aug 1, 2016
 #2
avatar+118694 
+16
Best Answer

Suppose the polynomial p(x)=x^3+ax^2+bc+c has the property that the mean of its zeroes, the product of its zeroes, and the sum of its coefficients are all equal. If the y-intercept of the graph of y=p(x) is 2, what is b?

 

for this answer I will assume it is a typo

 

The y intercept is the constant so c=2

 

p(x)=x3+ax2+bx+cp(x)=x3+ax2+bx+2

Let the zeros be α,β,andγα+β+γ=a1soα+β+γ3=a3αβγ=c1=2The coefficients are 1, a and bsoα+β+γ3=αβγ=1+a+ba3=2=1+a+ba=6 2=1+6+b2=7+bb=9

Melody Aug 1, 2016
 #3
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+1

' The coefficients are 1, a and b ... '

Why isn't c a coefficient ?

 Aug 1, 2016
 #4
avatar
+1

The correct answer however is -11

 Feb 28, 2017

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