Suppose you have a right triangle with an angle θ. the side opposite to θ has length 12 and the hypotenuse has length 13.
find the length of the side adjacent to θ
+130511 The sides of this triangle form what's known as a "Pythagorean Triple." It's probably one you should memorize, because it occurs frequently. The remaining side is 5. Proof:
13^2 - 12^2 = (adjacent side)^2
169 - 144 = (adjacent side)^2
25 = (adjacent side)^2 ....... take the square root of both sides
5 = (adjacent side)
So, the Pythagorean Triple is just 5-12-13. Note a seemingly odd thing (not really)...all multiples of these numbers will be Pythagorean Triples, too..i.e., 10-24-26 .......15-36-39, etc.
+130511 The sides of this triangle form what's known as a "Pythagorean Triple." It's probably one you should memorize, because it occurs frequently. The remaining side is 5. Proof:
13^2 - 12^2 = (adjacent side)^2
169 - 144 = (adjacent side)^2
25 = (adjacent side)^2 ....... take the square root of both sides
5 = (adjacent side)
So, the Pythagorean Triple is just 5-12-13. Note a seemingly odd thing (not really)...all multiples of these numbers will be Pythagorean Triples, too..i.e., 10-24-26 .......15-36-39, etc.
