WHAT IS THE SURFACE AREA OF A SQUARE BASED PYRAMID WHOSE LATERAL FACES ARE ISOSCELES TRIANGLES WITH BASE LENGTH 10 INCHES AND LATERAL HEIGHT 8 INCHES.
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WHAT IS THE SURFACE AREA OF A SQUARE BASED PYRAMID WHOSE LATERAL FACES ARE
ISOSCELES TRIANGLES WITH BASE LENGTH 10 INCHES AND LATERAL HEIGHT 8 INCHES.
AreaF = (1/2)(10 in)(8 in) = 40 in2 Area of a single face
4 • 40 in2 = 160 in2 Area of all four faces
AreaB = (10 in)(10 in) = 100 in2 Area of base
the surfaces added together = 260 in2 Area of entire pyramid
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