What is the surface are of a pyramid that has the length of 5 the width of 5 and the height of 5
+130516 Assuming a square pyramid, the base is easy....it's just 5^2 = 25 square units
We need to find the slant height.......this is given by :
√ [5^2 + 2.5^2] = about 5.6 units
So.....the area of the sides =
4 * (1/2) * (side length) * (slant height)
4 * (1/2)(5)(5.6) = 56 square units
So....the total surface area ≈ [ 25 + 56] square units ≈ 81 square units
