Susan bought a number of sweets. She wanted to give each of her friends 8 sweets but found herself short of 5 sweets. In the end, she gave each of her friends 6 sweets and had 19 sweets left. How many sweets did she have initially?(please do it in a specific primary5 way as my nephew is primary 5)
+8 Use common multiples although it is the most retarded way,P5 pupils use this method
Multiples of 8(-5): 3 11 19 27 35 43
Multiples of 6(+19): 25 31 37 43
Ans:43
+26367 I set y are her friends and x are the sweets.
Then we have first 8y-5=x and second 6y+19=x also.
We can set equal 8y-5=6y+19
So we have 2y=24 or y=12.
She has 12 friends.
We go back to the first equation and set for y the number 12.
8*12-5=x and x=96-5 or x=91
She has 91 sweets
+8 Use common multiples although it is the most retarded way,P5 pupils use this method
Multiples of 8(-5): 3 11 19 27 35 43
Multiples of 6(+19): 25 31 37 43
Ans:43
