The admission fee at an amusement park is 1.5 dollars for children and 4 dollars for adults. On a certain day, 272 people entered the park, and the admission fees collected totaled 808 dollars. How many children and how many adults were admitted?

Guest Jan 27, 2021

#1**+3 **

Let's say the number of children that entered the park is \(c\)

The total price of all the children's fees is, well, \(1.5c\)

Same for adults, the varible is \(a\), and the total price is \(4a\)

Now we have two equations

\(1.5c + 4a = 808 \)

\( c+a=272\)

Easy enough to solve

\(c=112, a=160\)

**The number of children admitted is 112, and the total number of aldults admitted is 160**

Check my work:

\(112+160=272\)

and \(168+640=808\)

(168 is 112 times 1.5, and 640 is 4 times 160)

**Children = 112**

**Adults = 160**

Please correct me if I'm wrong

QueenOfAllTrades Jan 28, 2021