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I'm just wondering will this system of equations lead to \(PX=PY\). If it does can you show me how you got it?

\(\begin{array}{lcl} 2.5PX & = & \dfrac{5}{24}y(h) \\ 3.5PY & = & \dfrac{7}{24}y(h) \end{array}\)

 May 2, 2020

Best Answer 

 #1
avatar+30604 
+4

2.5PX = 5y(h)/24    (1)

 

3.5PY = 7y(h)/24    (2)

 

Multiply both sides of (1) by 24/5

2.5PX*24/5 = y(h)     (3)

 

Use (3) to replace y(h) in (2)

 

3.5PY = (7/24)*(2.5PX*24/5)

3.5PY = 7/5PX

PX = 3.5*(5/7)*PY

PX = (7/2)*(5/7)*PY

PX = 5/2PY  or PX = 2.5PY

 May 2, 2020
 #1
avatar+30604 
+4
Best Answer

2.5PX = 5y(h)/24    (1)

 

3.5PY = 7y(h)/24    (2)

 

Multiply both sides of (1) by 24/5

2.5PX*24/5 = y(h)     (3)

 

Use (3) to replace y(h) in (2)

 

3.5PY = (7/24)*(2.5PX*24/5)

3.5PY = 7/5PX

PX = 3.5*(5/7)*PY

PX = (7/2)*(5/7)*PY

PX = 5/2PY  or PX = 2.5PY

Alan May 2, 2020

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