I'm just wondering will this system of equations lead to \(PX=PY\). If it does can you show me how you got it?
\(\begin{array}{lcl} 2.5PX & = & \dfrac{5}{24}y(h) \\ 3.5PY & = & \dfrac{7}{24}y(h) \end{array}\)
2.5PX = 5y(h)/24 (1)
3.5PY = 7y(h)/24 (2)
Multiply both sides of (1) by 24/5
2.5PX*24/5 = y(h) (3)
Use (3) to replace y(h) in (2)
3.5PY = (7/24)*(2.5PX*24/5)
3.5PY = 7/5PX
PX = 3.5*(5/7)*PY
PX = (7/2)*(5/7)*PY
PX = 5/2PY or PX = 2.5PY
