(5/4)x - 3 =(1/6)y
(2/5)x + (1/5)y=(9/5)
(5/4)x - 3 =(1/6)y,
(2/5)x + (1/5)y=(9/5)
Solve the following system:
{(5 x)/4-3 = y/6 | (equation 1)
(2 x)/5+y/5 = 9/5 | (equation 2)
Express the system in standard form:
{(5 x)/4-y/6 = 3 | (equation 1)
(2 x)/5+y/5 = 9/5 | (equation 2)
Subtract 8/25 × (equation 1) from equation 2:
{(5 x)/4-y/6 = 3 | (equation 1)
0 x+(19 y)/75 = 21/25 | (equation 2)
Multiply equation 1 by 12:
{15 x-2 y = 36 | (equation 1)
0 x+(19 y)/75 = 21/25 | (equation 2)
Multiply equation 2 by 75:
{15 x-2 y = 36 | (equation 1)
0 x+19 y = 63 | (equation 2)
Divide equation 2 by 19:
{15 x-2 y = 36 | (equation 1)
0 x+y = 63/19 | (equation 2)
Add 2 × (equation 2) to equation 1:
{15 x+0 y = 810/19 | (equation 1)
0 x+y = 63/19 | (equation 2)
Divide equation 1 by 15:
{x+0 y = 54/19 | (equation 1)
0 x+y = 63/19 | (equation 2)
Collect results:
Answer: | x = 54/19 and y = 63/19
