the sum of two numbers is 97. the larger number is 10 more than twice the smaller number. find the two numbers
Let the smaller number be x
Then the larger number is:(2x) +10, so we have
x +2x +10=97
3x=97-10=87 Divide both sides by 3 and we have
x=87/3=29 This is the smaller number.
(29*2) + 10=68 This is the larger number, so that:
29 + 68=97, which is your answer.