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the sum of two numbers is 97. the larger number is 10 more than twice the smaller number. find the two numbers

 Sep 15, 2015

Best Answer 

 #2
avatar+130516 
+5

Let the smaller number be x....then the larger number is  2x + 10....so we have

 

[x] +  [2x + 10]  = 97    simplify

 

3x + 10  = 97      subtract 10 from both sides

 

3x = 87        divide both sides by 3

 

x = 29    and this is the smaller number

 

And   2(29) + 10  =  68  is the larger number

 

 

 

cool cool cool

 Sep 15, 2015
 #1
avatar
+5

Let the smaller number be x

Then the larger number is:(2x) +10, so we have

x +2x +10=97

3x=97-10=87 Divide both sides by 3 and we have

x=87/3=29 This is the smaller number.

(29*2) + 10=68 This is the larger number, so that:

29 + 68=97, which is your answer.

 Sep 15, 2015
 #2
avatar+130516 
+5
Best Answer

Let the smaller number be x....then the larger number is  2x + 10....so we have

 

[x] +  [2x + 10]  = 97    simplify

 

3x + 10  = 97      subtract 10 from both sides

 

3x = 87        divide both sides by 3

 

x = 29    and this is the smaller number

 

And   2(29) + 10  =  68  is the larger number

 

 

 

cool cool cool

CPhill Sep 15, 2015

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